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54=5x^2
We move all terms to the left:
54-(5x^2)=0
a = -5; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-5)·54
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*-5}=\frac{0-6\sqrt{30}}{-10} =-\frac{6\sqrt{30}}{-10} =-\frac{3\sqrt{30}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*-5}=\frac{0+6\sqrt{30}}{-10} =\frac{6\sqrt{30}}{-10} =\frac{3\sqrt{30}}{-5} $
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